hmz007
36ed224bac
Signed-off-by: hmz007 <hmz007@gmail.com> Change-Id: Ib87fdbe7a0be7dc961af3500fe9ea4589a127f9f
37 lines
1.1 KiB
C
37 lines
1.1 KiB
C
#ifndef _SPLITSTR_H_
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#define _SPLITSTR_H_
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/*
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* Synopsis
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*
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* const char **splitstr(const char *str, const char *separator, int *argcount)
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*
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* Description
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* This function splits a string (str) into components that are separated by
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* one or more of the characters in the (separator) string. An array of
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* strings is returned, along with argcount being set to the number of strings
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* found. Argcount can be NULL. There will always be a NULL element in the
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* array after the last valid element. If an error occurs, NULL will be
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* returned and argcount will be set to zero.
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*
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* To rid yourself of the memory allocated for splitstr(), pass the return
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* value from splitstr() unmodified to splitstr_free():
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*
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* void splitstr_free( const char ** return_from_splitstr );
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*
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*/
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const char **
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splitstr(const char *, const char *, int *);
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/*
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* splitster_free( const char ** )
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*
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* This takes the return value from splitster() and free()s memory
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* allocated by splitster. Assuming: ret=splitster(...), this
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* requires that ret and *ret returned from splitster() have not
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* been modified.
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*/
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void
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splitstr_free( const char ** );
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#endif
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